NCERT Class 10th solution of Exercise 6.1 NCERT Class 10th solution of Exercise 6.2 NCERT Class 10th solution of Exercise 6.4 NCERT Class 10th solution of Exercise 6.5 NCERT Class 10th Maths Projects Exercise 6.3 Q1. State which pairs of triangles in Figure are similar. Write the similarity criterion used by you for answering the question and also write the pairs of similar triangles in the symbolic form : Sol. : `text{In }triangletext{ABC and }triangletext{PQR}` `angletext{A}=angletext{P}` `angletext{B}=angletext{Q}` `angletext{C}=angletext{R}` `triangletext{ABC}∼triangletext{PQR}``text{ [By AAA]}` `text{Answer :}` `text{Yes, AAA, }``triangletext{ABC}∼triangletext{PQR}`. Sol. : `text{In } triangletext{ABC and }triangletext{PQR}` `(text{AB})/(text{QR})=2/4=1/2` `(text{AC})/(text{PQ})=3/6=1/2` `(text{BC})/(text{PR})=(2.5)/5=1/2` `(text{AB})/(text{QR})=(text{AC})/(text{PQ})=(text{AB})/(text{QR})=1/2` `triangletext{ABC}∼triangletext{PQR}``text{ [By SSS]}` `text{Answer :}` `text{Yes, SSS,}

NCERT Class 10th solution of Exercise 6.1 NCERT Class 10th solution of Exercise 6.2 NCERT Class 10th solution of Exercise 6.3 NCERT Class 10th solution of Exercise 6.5 NCERT Class 10th Maths Projects Exercise 6.4 Q1. Let  `triangleABC∼triangleDEF` and their areas be, respectively, `64cm^2` and `121cm^2`. If `EF=15.4` cm, find `BC`. `text{Sol.}` `text{Given,}` `triangle text{ABC} ∼ triangle text{DEF}` `text{so that}` `(text{AB})/(text{DE}) = (text{BC})/(text{EF}) = (text{CA})/(text{FD})` `(ar(text{ABC}))/(ar(text{DEF})) = ((text{BC})/(text{EF}))^2` `64/121 = ((text{BC})/15.4)^2` `(8/11)^2 = ((text{BC})/15.4)^2` `text{BC} = (8times15.4)/11` `text{BC} = 123.2/11` `text{BC} = 11.2 text{ cm}` `text{Answer:}` `text{BC} = 11.2 text{ cm}.` Q2. Diagonals of a trapezium `ABCD` with `AB∥DC` intersect each other at the point `O`. If `AB=2CD`, find the ratio of the areas of triangles `AOB` and `COD`. `text{Sol.}` `text{Given,}` `text{ABCD is trapezium with AB||DC and }``text{AB = 2CD}` `text{In}tri

Chapter 9 Algebraic Expressions and Identities NCERT Class 8th solution of Exercise 9.2 NCERT Class 8th solution of Exercise 9.3 NCERT Class 8th solution of Exercise 9.4 NCERT Class 8th solution of Exercise 9.5 Exercise 9.1 Q1. Identify the terms, their coefficients for each of the following expressions. i) `5xyz^2 - 3zy,` ii) `1 + x + x^2,` iii) `4x^2y^2 - 4x^2y^2z^2 + z^2,` iv) `3 - pq + qr - rp,` v) `x/2 + y/2 - xy,` vi) `0.3a - 0.6ab + 0.5b,` `text{Answer:}`

Chapter 9 Algebraic Expressions and Identities NCERT Class 8th solution of Exercise 9.1   NCERT Class 8th solution of Exercise 9.3 NCERT Class 8th solution of Exercise 9.4 NCERT Class 8th solution of Exercise 9.5 Exercise 9.2 Q1. Find the product of the following pairs of monomials. i) `4, 7p` ii) `-4p, 7p` iii) `-4p, 7pq` iv) `4p^3, -3p` v) `4p, 0` `text{Sol.}` i) `4times 7p``= 28p` ii) `-4ptimes 7q``= -28p^2` iii) `-4ptimes 7pq``= -28p^2q` iv) `4p^3times -3p``= -12p^4` v) `4ptimes 0``= 0`

Chapter 6 Squares and Square Roots NCERT Class 8th solution of Exercise 6.1 NCERT Class 8th solution of Exercise 6.2 NCERT Class 8th solution of Exercise 6.3 Exercise 6.4 Q1. Find the square root of each of the following numbers by Division Method. i) `2304` ii) `4489` iii) `3481` iv) `529` v) `3249` vi) `1369` vii) `5776` viii) `7921` ix) `576` x) `1024` xi) `3136` xii) `900` `text{Sol.}` i) `2304` `text{Answer:}` `sqrt2304 = 48` ii) `4489` `text{Answer:}` `sqrt4489 = 67` iii) `3481` `text{Answer:}` `sqrt3481 = 59` iv) `529` `text{Answer:}` `sqrt529 = 23` v) `3249` `text{Answer:}` `sqrt3249 = 57` vi) `1369` `text{Answer:}` `sqrt1369 = 37` vii) `5776` `text{Answer:}` `sqrt5776 = 76` viii) `7921` `text{Answer:}` `sqrt7921 = 89` ix) `576` `text{Answer:}` `sqrt576 = 24` x) `1024` `text{Answer:}` `sqrt1024 = 32` xi) `3136` `text{Answer:}` `sqrt3136 = 56` xii) `900` `text{Answer:}` `sqrt900 = 30`