8th Maths 3.1
NCERT Class 8th solution of Exercise 3.2
NCERT Class 8th solution of Exercise 3.3
NCERT Class 8th solution of Exercise 3.4
NCERT Class 8th solution of Exercise 2.1
Exercise 3.1
Q1. Given here are some figures.
Classify each of them on the basis of the following.
a) Simple curved
b) Simple closed curved curve
c) Polygon
d) Convex polygon
e) Concave polygon
Answer:
a) 1,2,5,6,7
b) 1,2,5,6,7
c) 1,2
d) 2
e) 1
Q2. How many diagonals does each of the following have?
a) A convex quadrilateral
b) A regular hexagon
c) A triangle
Answer:
a) 2, b) 9, c) 0
Q3. What is the sum of the measures of the angles of a convex quadrilateral? Will this property hold if the quadrilateral is not convex? (Make a non-convex quadrilateral and try!)
Answer:
360∘, yes.
Q4. Examine the table. (Each figure is divided into triangles and the sum of the angles deduced from that.)
What can you say about the angle sum of a convex polygon with number of sides?
a) 7
b) 8
c) 10
d) n
a)
Sol.
Number of sides 7
Angle sum = (n - 2)×180∘
=(7-2)×180∘
=5×180∘
=900∘
Answer:
900∘.
b)
Sol.
Number of sides 8
Angle sum = (n - 2)×180∘
=(8-2)×180∘
=6×180∘
=1080∘
Answer:
1080∘.
c)
Sol.
Number of sides 10
Angle sum = (n - 2)×180∘
=(10-2)×180∘
=8×180∘
=1440∘
Answer:
1440∘.
d)
Sol.
Number of sides n
Angle sum = (n - 2)×180∘
Answer:
(n - 2)180∘.
Q5. What is a regular polygon?
State the name of a regular polygon of
i) 3 sides
ii) 4 sides
iii) 6 sides
Answer:
A polygon with equal sides and equal angles.
i)
Answer
Equilateral triangle
ii)
Answer
Square.
iii)
Answer
Regular haxagon
Q6. Find the angle measure x in the following figures.
Sol.
Number of sides 4
Angle sum = (n - 2)×180∘
=(4-2)×180∘
=2×180∘
=360∘
x +50∘+130∘+120∘=360∘
x =360∘-300∘
x =60∘
Answer
60∘.
b)
Sol.
Number of sides 4
Angle sum = (n - 2)×180∘
=(4-2)}×180∘
=2×180∘
=360∘
x +60∘+70∘+90∘=360∘
x =360∘-220∘
x =140∘
Answer
140∘
c)
Sol.
Number of sides 5
Angle sum = (n - 2)×180∘
=(5-2)}×180∘
=3×180∘
=540∘
x + x +30∘+(180∘-70∘)+(180∘-60∘)=540∘
2x +30∘+110∘+120∘=540∘
2x =540∘-260∘
x =280∘2
x =140∘
Answer
140∘.
d)
Sol.
Number of sides 5
Angle sum = (n - 2)×180∘
=(5-2)}×180∘
=3×180∘
=540∘
x + x + x + x + x =540∘
x =540∘5
x =108∘
Answer
108∘.
Q7.
a) Find x+y+z
Sol.
x+90∘=180∘_[By linear pair]
x=180∘-90∘
x=90∘
z+30∘=180∘_[By linear pair]
z=180∘-30∘
z=150∘
y=(90∘+30∘)_[By exterior angle]
y=120∘
x+y+z=90∘+150∘+120∘
=360∘
Answer:
360∘
b) Find x+y+z+w
Sol.
x+120∘=180∘[By linear pair]
x=180∘-120∘
x=60∘
y+80∘=180∘_[By linear pair]
y=180∘-80∘
y=100∘
z+60∘=180∘_[By liner pair]
z=180∘-60∘
z=120∘
By angle sum property of quadrilateral
∠zwx=360∘-(120∘+80∘+60∘)
∠zwx=360∘-260∘
∠zwx=100∘
w+100∘=180∘_[by linear pair]
w=180∘-100∘
w=80∘
x+y+z+w=60∘+100∘+120∘+80∘
=360∘
Answer:
360∘.
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