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8th Maths 6.3

Chapter 6 Squares and Square Roots NCERT Class 8th solution of Exercise 6.1 NCERT Class 8th solution of Exercise 6.2 NCERT Class 8th solution of Exercise 6.4 Exercise 6.3 Square root you must learn. 12=1=1 22=4=2 32=9=3 42=16=4 52=25=5 62=36=6 72=49=7 82=64=8 92=81=9 102=100=10 112=121=11 122=144=12 132=169=13 142=196=14 152=225=15 162=256=16 172=289=17 182=324=18 192=361=19 202=400=20 212=441=21 222=484=22 232=529=23 242=756=24 252=625=25 262=676=26 272=729=27 282=224=28 292=841=29 302=900=30 312=961=31 322=1024=32 332=1089=33 342=1156=34 352=1225=35 362=1296=36 372=1369=37 382=1444=38 392=1521=39 402=1600=40 `41^2=sqrt{1...

8th Maths 6.2

Chapter 6 Squares and Square Roots NCERT Class 8th solution of Exercise 6.1 NCERT Class 8th solution of Exercise 6.3 NCERT Class 8th solution of Exercise 6.4 Exercise 6.2 Q1. Find the square of the following numbers. i) 32 ii) 35 iii) 86 iv) 93 v) 71 vi) 46 Sol. i) 322 =(30+2)2 =30(30+2)+2(30+2) =302+30×2+2×30+22 =900+60+60+4 =1024 Answer: 1024. ii) 352 =(30+5)2 =30(30+5)+5(30+5) =302+30×5+5×30+52 =900+150+150+25 =1225 Answer: 1225. iii) 862 =(80+6)2 =80(80+6)+6(80+6) =802+80×6+6×80+62 =6400+480+480+36 =7396 Answer: 7396. iv) 932 =(90+3)2 =90(90+3)+3(90+3) =902+90×3+3×90+32 =8100+270+270+9 =8649 Answer: 8649. v) 712 =(70+1)2 =70(70+1)+1(70+1) =702+70×1+1×70+12 =4900+70+70+1 =5041 `t...

8th Maths 6.1

Chapter 6 Squares and Square Roots NCERT Class 8th solution of Exercise 6.2 NCERT Class 8th solution of Exercise 6.3 NCERT Class 8th solution of Exercise 6.4 Exercise 6.1 Square you must learn. 12=1 22=4 32=9 42=16 52=25 62=36 72=49 82=64 92=81 102=100 112=121 122=144 132=169 142=196 152=225 162=256 172=289 182=324 192=361 202=400 212=441 222=484 232=529 242=756 252=625 262=676 272=729 282=224 292=841 302=900 312=961 322=1024 332=1089 342=1156 352=1225 362=1296 372=1369 382=1444 392=1521 402=1600 412=1681 422=1764 432=1849 442=1936 452=2025 462=2116 472=2209 482=2304 492=2401 502=2500 Q1. what will be the unit digit of the squares of the following numbers? i) 81 ii) 272 iii) 799 iv) 3853 v) 1234 vi) 26387 vii) 52698 viii) 99880 ix) 12796 x) 55555 Sol: i) The unit digit of 81 is 1,`text{ so tha...

10th Maths 12.3

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NCERT Class 10th solution of Exercise 12.1 NCERT Class 10th solution of Exercise 12.2 NCERT Class 10th solution of Exercise 13.1 NCERT Class 10th Maths Projects Exercise 12.3 Q1. Find the area of the shaded region in Figure, if PQ = 24 cm, PR = 7 cm and O is the centre of the circle. Sol. In rightQPR by Pythagoras theorem. RQ = (PQ)2+(RP)2 =(24)2+(7)2 =576+49 =625 =25 r=252 Area of semicircle QPR = 12πr2 =12×227×(252)2 =11×62528 =687528 cm2 Area of right RPQ=12×RP×PQ =12×7×24 =84 cm2 Area of the shaded region = ar of semicircle QPR - ar of RPQ =687528-84 =6875-235228 =452328 cm2    Answer The area of shaded region is 452328 cm2.

10th Maths12.2

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NCERT Class 10th solution of Exercise 12.1 NCERT Class 10th solution of Exercise 12.3   NCERT Class 10th Maths Projects Exercise 12.2 Unless stated otherwise, use π=227. Q1. Find the area of a sector of a circle with radius 6 cm if angle of the sector is 60. Sol. Area of sector = θ360×πr2                         = 60360×227×(6)2                         = 6×66×227                         = 6×227                         = 1327 cm2 Answer Area of sector 1327 cm2.

10th Maths 12.1

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NCERT Class 10th solution of Exercise 12.3   NCERT Class 10th solution of Exercise 12.2   NCERT Class 10th Maths Projects Exercise 12.1 Unless stated otherwise, use π=227. Q1. The radii of two circles are 19 cm and 9 cm respectively. Find the radius of the circle which has circumference equal to the sum of the circumferences of the two circles. Sol. circumference of big circle = circumference of (circle1+ circle2) 2πR = 2πr1 + 2πr2 2πR = 2π{19+9} R = 28 cm.  Answer : Radius = 28 cm. 

8th Maths 7.1

Chapter 7 Cubes and Cube Roots NCERT Class 8th solution of Exercise 7.2 Exercise 7.1 Cube you must learn 13=1 23=8 33=27 43=64 53=125 63=216 73=343 83=512 93=729 103=1000 113=1331 123=1728 133=2197 143=2744 153=3375 163=4096 173=4913 183=5832 193=6859 203=8000 Q1. Which of the following numbers are not perfect cubes? i) 216 ii) 128 iii) 1000 iv) 100 v) 46656 Sol. i) Prime factorisations of 216=2×2×2̲×3×3×3̲ Answer: 216 is the perfect cube. ii) Prime factorisations of 128=2×2×2̲×2×2×2̲×2 Answer: 128 is not perfect cube iii) Prime factorisations of 1000=2×2×2̲×5×5×5̲ Answer: 1000 is perfect cube iv) Prime factorisations of 100=2×2̲×5×5̲ Answer: `text{1...

8th Maths 7.2

Chapter 7 Cubes and Cube Roots NCERT Class 8th solution of Exercise 7.1 Exercise 7.2 Cube Roots you must learn 31=1 38=2 327=3 364=4 3125=5 3216=6 3343=7 3512=8 3729=9 31000=10 31331=11 31728=12 32197=13 32744=14 33375=15 34096=16 34913=17 35832=18 36859=19 38000=20 Q1 Find the cube root of each of the following numbers by prime factorisation method. i) 64 ii) 512 iii) 10648 iv) 27000 v) 15625 vi) 13824 vii) 110592 viii) 46656 ix) 175616 x) 91125 Sol. i) Prime factorisations of 364=2×2×2̲×2×2×2̲ =2×2 =4 Answer: The cuberoot of 64 is 4. ii) Prime factorisations of `root [3]{512} =underline(2times2times2)times underline(2times2times2)times und...

8th Maths 3.3

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NCERT Class 8th solution of exercise 3.1 NCERT Class 8th solution of Exercise 3.2 NCERT Class 8th solution of Exercise 3.4 Exercise 3.3 Q1. Given a parallelogram ABCD. Complete each statement with the definition or property used. i) AD = .......... ii) DCB = ............ iii) OC = ........... iv) mDAB+mCDA = .......... Answer: i) BC (Opposite sides are equal) ii) DAB (Opposite angles are equal) iii) OA (Diagonals bisect each other) iv) 180(Interior opposite angles,¯AB¯DC)

8th Maths 3.2

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NCERT Class 8th solution of Exercise 3.1 NCERT Class 8th solution of Exercise 3.3 NCERT Class 8th solution of Exercise 3.4 Exercise 3.2 Q1. Find the following figures. a) Sol. We know that Sum of the external angles of a polygon is 360. x +125+125=360 x=360-250 x=110 Answer: x=110. b) Sol. We know that Sum of the external angles of a polygon is 360. x +90+60+90+70=360 x=360-310 x=50 Answer: x=50

8th Maths 3.1

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NCERT Class 8th solution of Exercise 3.2 NCERT Class 8th solution of Exercise 3.3 NCERT Class 8th solution of Exercise 3.4 NCERT Class 8th solution of Exercise 2.1 Exercise 3.1 Q1. Given here are some figures. Classify each of them on the basis of the following. a) Simple curved b) Simple closed curved curve c) Polygon d) Convex polygon e) Concave polygon Answer: a) 1,2,5,6,7 b) 1,2,5,6,7 c) 1,2 d) 2 e) 1

8th Math 3.4

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NCERT Class 8th solution of Exercise 3.1 NCERT Class 8th solution of Exercise 3.2 NCERT Class 8th solution of Exercise 3.3 Exercise 3.4 Q1. State whether True or False. a) All rectangles are squares b) All rhombuses are parallelograms c) All squares are rhombuses and also rectangles d) All squares are not parallelograms e) All kites are rhombuses f) All rhombuses are kites g) All parallelograms are trapeziums h) All squares are trapeziums. Answer: a) false, b) true, c) true, d) false, e) false, f) true, g) true, h) true. 

8th Maths 2.4

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Chapter 2 Linear Equations in One Variable NCERT Class 8th solution of Exercise 2.1 NCERT Class 8th solution of Exercise 2.2 NCERT Class 8th solution of Exercise 2.3 NCERT Class 8th solution of Exercise 2.5 NCERT Class 8th solution of Exercise 2.6 Exercise 2.4 Q1. Amina thinks of a number and subtracts 52 from it. She multiplies the result by 8. The result now obtained is 3 times the same number she thought of. What is the number? Sol. Let Amina thinks of a number is x According to question (x-52)×8=3×x 8x - 20 = 3x 8x - 3x = 20 5x = 20 x=205 x=4 Answer: The number is 4.

8th Maths 2.2

Chapter 2 Linear Equations in One Variable NCERT Class 8th solution of Exercise 2.1 NCERT Class 8th solution of Exercise 2.3 NCERT Class 8th solution of Exercise 2.4 NCERT Class 8th solution of Exercise 2.5 NCERT Class 8th solution of Exercise 2.6 Exercise 2.2 Q1. If you subtract 12 from a number and multiply the result by 12, you get 18. What is the number? Solution : Let a number be x According to question (x-12)×12=18 Multiply 2 on both sides. (x-12)×12×2=18×2 x-12=14 Add 12 on both sides x-12+12=14+12 x=2+44×2 x=68 x=34 Answer : The number is 34.

8th Maths 2.6

Chapter 2 Linear Equations in One Variable NCERT Class 8th solution of Exercise 2.1 NCERT Class 8th solution of Exercise 2.2 NCERT Class 8th solution of Exercise 2.3 NCERT Class 8th solution of Exercise 2.4 NCERT Class 8th solution of Exercise 2.5 Exercise 2.6 Solve the following equations. Q1. 8x - 33x=2 Sol. 8x - 33x=2 8x - 3=3x×2 8x - 3 = 6x 8x - 6x = 3 2x=3 x=32 Answer: x=32

8th Maths 2.5

Chapter 2 Linear Equations in One Variable NCERT Class 8th solution of Exercise 2.1 NCERT Class 8th solution of Exercise 2.2 NCERT Class 8th solution of Exercise 2.3 NCERT Class 8th solution of Exercise 2.4 NCERT Class 8th solution of Exercise 2.6 Exercise 2.5 Solve the following linear equations. Q1. x2-15=x3+14 Sol. x2-15=x3+14 x2-x3=14+15 3x - 2x6=5+420 x6=920 x=6×920 x=3×910 x=2710 Answer: x=2710.

8th Maths 2.3

Chapter 2 Linear Equations in One Variable NCERT Class 8th solution of Exercise 2.1 NCERT Class 8th solution of Exercise 2.2 NCERT Class 8th solution of Exercise 2.4 NCERT Class 8th solution of Exercise 2.5 NCERT Class 8th solution of Exercise 2.6 Exercise 2.3 Solve the following equations and  check your results. Q1. 3x = 2x + 18 Solution: 3x = 2x + 18 3x - 2x = 18 x = 18 Check the result 3×18=2×18+18 54=36+18 54=54 Answer: x = 18.