8th Maths 8.2
Chapter 8
Comparing Quantities
NCERT Class 8th Solution of Exercise 8.1
NCERT Class 8th Solution of Exercies 8.3
EXERCISE 8.2
1. A man got a 10% increase in his salary. If his new salary is ₹ 1,54,000, find his original salary.Solution:
salary increase 10%
new salary ₹ 154000
original salary=new salary×100100+increase%
=154000×100100+10
=15400000110
=₹140000
Answer:
His original salary was ₹ 140000.
2. On Sunday 845 people went to the Zoo. On Monday only 169 people went. What is the percent decrease in the people visiting the Zoo on Monday?
Solution:
No. of people decrease = Sunday - Monday
=845-169
=676
Decrease percent
=No. of people decreaseNo of people visit on Sunday×100
=676845×100
=80%
Answer:
Decrease percent 80%.
3. A shopkeeper buys 80 articles for ₹ 2,400 and sells them for a profit of 16%. Find the selling price of one article.
Solution:
Cost price of 1 article=240080=30
Profit 16%
Selling price =?
SP=CP(100+Profit)100
=30(100+16)100
=30×116100
=34.80
Answer:
The SP of an article is ₹ 34.80.
4. The cost of an article was ₹ 15,500. ₹.450 were spent on its repairs. If it is sold for a profit of 15%, find the selling price of the article.
Solution:
Cost price ₹ 15500
Repair cost ₹ 450
Actual cost 15500 + 450 = 15950
Profit = 15%
Selling Price = ?
SP=CP(100+Profit)100
=15950(100+15)100
=15950×115100
=1834250100
=18342.50
Answer:
The selling price of the article is ₹ 18342.50.
5. A VCR and TV were bought for ₹ 8,000 each. The shopkeeper made a loss of 4% on the VCR and a profit of 8% on the TV. Find the gain or loss percent on the whole transaction.
Solution:
For VCR
CP ₹ 8000
Loss 4%
SP = ?
SP=CP(100-Loss)100
=8000(100-4)100
=8000×96100
=7680
For TV
CP ₹ 8000
Profit 8%
SP = ?
SP=CP(100+Profit)100
=8000(100+8)100
=8000×108100
=8640
Total CP = 8000+8000=16000
Total SP = 7680+8640=16320
SP>CP hence Profit
Profit = SP-CP
Profit = 16320-16000 = 320
Profit%=Profit×100CP
=320×10016000
=2%
Answer:
2% gain in the whole transaction.
6. During a sale, a shop offered a discount of 10% on the marked prices of all the items. What would a customer have to pay for a pair of jeans marked at 1450 and two shirts marked at 850 each?
Solution:
Marked Price of jeans ₹ 1450
Marked Price of shirts 2×850=₹1700
Total Marked Price = 1450 + 1700 = ₹ 3150
Discount 10%
SP = ?
SP=MP(100-Discount)100
=3150(100-10)100
=3150×90100
=2835
Answer:
Customer have to pay ₹ 2835.
7. J. A milkman sold two of his buffaloes for ₹ 20,000 each. On one he made a gain of 5% and on the other a loss of 10%. Find his overall gain or loss. (Hint: Find CP of each)
Solution:
First Buffalo
SP = ₹ 20000
Gain 5%
CP = ?
CP=SP×100100+gain
=20000×100100+5
=2000000105
=40000021
=19047.62
Second Buffalo
SP = ₹ 20000
Loss 10%
CP = ?
CP=SP×100100-loss
=20000×100100-10
=200000090
=2000009
=22222.22
Total CP=19047.62+22222.22=41269.84
Total SP=20000+20000=40000
CP>SP hence Loss
Loss = CP - SP
=41269.84-40000
=1269.84
Answer:
Overall loss is ₹ 1269.84.
8. The price of a TV is 13,000. The sales tax charged on it is at the rate of 12%. Find the amount that Vinod will have to pay if he buys it.
Solution:
MP = 13000
Sales tax = 12%
CP = ?
CP=MP(100+ST)100
=13000(100+12)100
=13000×112100
=14560
Answer:
Vinod have to pay ₹ 14560.
9. Arun bought a pair of skates at a sale where the discount given was 20%. If the amount he pays is ₹ 1,600, find the marked price.
Solution:
Discount 20%
CP = ₹ 1600
MP = ?
MP=CP×100100-Discount
=1600×100100-20
=1600×10080
=2000
Answer:
The Marked price ₹ 2000.
10. I purchased a hair dryer for ₹ 5,400 including 8% VAT. Find the price before VAT was added.
Solution:
SP = 5400
VAT = 8%
CP = ?
CP=SP×100100+VAT
=5400×100100+8
=5400×100108
=5000
Answer:
The price before VAT is ₹ 5000.
11. An article was purchased for ₹ 1239 including GST of 18%. Find the price of the article before GST was added?
Solution:
SP = 1239
GST = 18%
CP = ?
CP=SP×100100+GST
=1239×100100+18
=1239×100118
=1050
Answer:
The price before GST ₹ 1050.
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